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JEE Main 202126 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Evening Shift
Subject
Mathematics
Chapter
Circle

JEE Main 2021 · 26 February · Evening Shift · Mathematics · Circle

If the locus of the mid-point of the line segment from the point...

If the locus of the mid-point of the line segment from the point (3,2)\left(3, 2\right) to a point on the circle, x2+y2=1{x}^{2} + {y}^{2} = 1 is a circle of radius rr, then rr is equal toIf the locus of the mid-point of the line segment from the point (3, 2) to a point on the circle, x ^ 2 + y ^ 2 = 1 is

Options

  1. A14\dfrac{1}{4}
  2. B11
  3. C13\dfrac{1}{3}
  4. D12\dfrac{1}{2}

Correct answer

D. 12\dfrac{1}{2}

Step-by-step solution

Given circle x2+y2=1{x}^{2} + {y}^{2} = 1

General coordinate on a given circle is \left(cos\theta, sin\theta\right) .

Given, h=h =\dfrac{cos\theta + 3}{2}⇒cosθ=2(h−32)...⇒ cos\theta = 2 \left(h - \dfrac{3}{2}\right) . . .\left(i\right)

k=k =\dfrac{sin\theta + 2}{2}⇒sinθ=2(k−1)...⇒ sin\theta = 2 \left(k - 1\right) . . .\left(ii\right)

Square \left(i\right)\text{ and }\left(ii\right)then add we get,

(h−32){\left(h - \dfrac{3}{2}\right)}^{2} + {\left(k - 1\right)}^{2} = {\left(\dfrac{1}{2}\right)}^{2}</p><p></p><p>⇒ r = 12</p><p><imgsrc="https://cdn−question−pool.getmarks.app/pyq/jeemain/74f0025b−531e−406d−9ac7−2584249000e1−image.png"style="width:344px;height:180px;"/></p>\dfrac{1}{2}</p><p><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_main/74f0025b-531e-406d-9ac7-2584249000e1-image.png" style="width: 344px; height: 180px;" /></p>

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