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JEE Main 201912 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
12 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Circle

JEE Main 2019 · 12 April · Morning Shift · Mathematics · Circle

If the angle of intersection at a point where the two circles with...

If the angle of intersection at a point where the two circles with radii 5cm5cm and 12cm12cm intersect is 90°90 °, then the length (in cm) of their common chord is:If the angle of intersection at a point where the two circles with radii 5cm and 12cm intersect is 90 ° , then the

Options

  1. A12013\dfrac{120}{13}
  2. B6013\dfrac{60}{13}
  3. C135\dfrac{13}{5}
  4. D132\dfrac{13}{2}

Correct answer

A. 12013\dfrac{120}{13}

Step-by-step solution

If the angle of intersection at a point where the two circles with radii 5cm and 12cm intersect is 90 ° , then the
∵C1P=5∵ {C}_{1}P = 5
C2P=12 and ∠C1PC2=90o{C}_{2}P = 12 \text{ and } ∠{C}_{1}P{C}_{2} = {90}^{o}
∴C1C2=13∴ {C}_{1}{C}_{2} = 13
∴\DeltaCC2P∴ \DeltaC{C}_{2}P
tanθ=125⇒sinθ=1213tan \theta = \dfrac{12}{5} ⇒ sin \theta = \dfrac{12}{13}
C1C2{C}_{1}{C}_{2} biscets the PQPQ at RR & C1C2⊥PQ{C}_{1}{C}_{2} ⊥ PQ
in \DeltaPC1R,sinθ=PR5\DeltaP{C}_{1}R, sin\theta = \dfrac{PR}{5}
⇒1213=PR5⇒PR=6013⇒ \dfrac{12}{13} = \dfrac{PR}{5} ⇒ PR = \dfrac{60}{13}
& PQ=2PR=12013PQ = 2PR = \dfrac{120}{13}
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