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JEE Main 20163 April
Exam
JEE Main
Year
2016
Date
3 April
Subject
Mathematics
Chapter
Circle

JEE Main 2016 · 3 April · Mathematics · Circle

The centres of those circles which touch the circle, x ^ 2 + y ^ 2...

The centres of those circles which touch the circle, x2+y2−8x−8y−4=0,{x}^{2} + {y}^{2} - 8x - 8y - 4 = 0, externally and also touch the xx - axis, lie onThe centres of those circles which touch the circle, x ^ 2 + y ^ 2 - 8x - 8y - 4 = 0, externally and also touch the x -The centres of those circles which touch the circle, x ^ 2 + y ^ 2 - 8x - 8y - 4 = 0, externally and also touch the x -

Options

  1. AA hyperbola
  2. BA parabola
  3. CA circle
  4. DAn ellipse which is not a circle

Correct answer

B. A parabola

Step-by-step solution

Given circle x2+y2−8x−8y−4=0x^{2} + y^{2} - 8x - 8y - 4 = 0

has centre \left(4, 4\right)andradiusand radius6.<br/><br/>Let(h,k).<br /><br />Let \left(h, k\right) be the centre of the circle which is touching the given circle externally

The centres of those circles which touch the circle, x ^ 2 + y ^ 2 - 8x - 8y - 4 = 0, externally and also touch the x -

Then

(h−4)2+(k−4)2=6+k\sqrt{{\left(h - 4\right)}^{2} + {\left(k - 4\right)}^{2}} = 6 + k

⇒h2−8h+16+k2−8k+16=36+12k+k2⇒h^{2} - 8h + 16 + k^{2} - 8k + 16 = 36 + 12k + k^{2}

⇒h2−8h−20k−4=0⇒h^{2} - 8h - 20k - 4 = 0 ,

Replacing hh by xandkx and k by yy, locus is

x2−8x−20y−4=0x^{2} - 8x - 20y - 4 = 0

Which is equation of parabola.

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