If one of the diameters of the circle, given by the equation, x 2 + y 2 - 4 x + 6 y - 12 = 0 , is a chord of a circle S , whose centre is at - 3 , 2 , then the radius of S is

Step-by-step solution

The centre of the given circle x 2 + y 2 - 4 x + 6 y - 12 = 0 is 2 , - 3 and the radius is 5 . ​​​​​​​ The distance between the centres 5 2 and radius is 5 . The triangle O P Q is a right angled triangle O Q = 5 2 2 + 5 2 = 5 3 2 = 5 3 Hence answer is 5 3