JEE Main202528 Jan 2025Evening ShiftMathematicsComplex NumberActual
If +i and +i are the roots of x^2-(3-2 i) x-(2 i-2)=0, i= -1 , then + is equal to :
Options
- A-2
- B6
- C-6
- D2
Correct answer
D. 2
Step-by-step solution
aligned & x^2-(3-2 i ) x -(2 i -2)=0 & x = (3-2 i ) (3-2 i )^2-4(1)(-(2 i -2)) 2(1) & == (3-2 i ) 9-4-12 i +8 i -8 2 & == 3-2 i -3-4 i 2 & = 3-2 i (1)^2+(2 i )^2-2(1)(2 i ) 2 & = 3-2 i (1-2 i ) 2 & 3-2 i +1-2 i 2 or 3-2 i -1+2 i 2 & 2-2 i or 1+0 i & So + =2(1)+(-2)(0)=2 aligned