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JEE Main 202116 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Morning Shift
Subject
Mathematics
Chapter
Complex Number

JEE Main 2021 · 16 March · Morning Shift · Mathematics · Complex Number

Let a complex number z, |z| ≠ 1 , satisfy log 1 2 ( |z| + 11 (|z| -...

Let a complex number z,∣z∣≠1z, \left|z\right| \ne 1, satisfy log12(∣z∣+11(∣z∣−1)2)≤2log\dfrac{1}{\sqrt{2}}\left(\dfrac{\left|z\right| + 11}{{\left(\left|z\right| - 1\right)}^{2}}\right) \le 2. Then, the largest value of \left|z\right| is equal to _________.

Options

  1. A88
  2. B77
  3. C66
  4. D55

Correct answer

B. 77

Step-by-step solution

log\dfrac{1}{\sqrt{2}}\left(\dfrac{\left|z\right| + 11}{{\left(\left|z\right| - 1\right)}^{2}}\right) \le 2</p><p></p><p>⇒ \dfrac{\left|z\right| + 11}{{\left(\left|z\right| - 1\right)}^{2}} \ge \dfrac{1}{2},{∵log⁡a(b)≤c⇒b≥acif0<a<1}, \left\{∵ \log_{a}\left(b\right) \le c ⇒ b \ge {a}^{c}if0 < a < 1\right\}

⇒2∣z∣+22≥(∣z∣−1)2⇒ 2\left|z\right| + 22 \ge {\left(\left|z\right| - 1\right)}^{2}, \left\{∵ \left|z\right| \ne 1 \text{ and } {\left(\left|z\right| - 1\right)}^{2} > 0\right\}</p><p></p><p>⇒ 2\left|z\right| + 22 \ge {\left|z\right|}^{2} + 1 - 2\left|z\right|</p><p></p><p>⇒ {\left|z\right|}^{2} - 4\left|z\right| - 21 \le 0</p><p></p><p>⇒ \left(\left|z\right| - 7\right)\left(\left|z\right| + 3\right) \le 0</p><p></p><p>⇒ \left|z\right| \le 7</p><p></p><p>∴Largestvalueof∣z∣Largest value of \left|z\right| is 77

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