JEE Main 201912 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 12 January
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Complex Number
JEE Main 2019 · 12 January · Evening Shift · Mathematics · Complex Number
Let z _ 1 and z _ 2 be two complex numbers satisfying | z _ 1 | = 9...
Let be two complex numbers satisfying . Then the minimum value of \left|{z}_{1} - {z}_{2}\right| is :
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
We have,
Centres of the circles are \left(0, 0\right){c}_{2} ≡ \left(3, 4\right){r}_{1} = 9{r}_{2} = 4⇒ {c}_{1}{c}_{2} = \sqrt{{3}^{2} + {4}^{2}} = 5{r}_{1} - {r}_{2} = 5⇒ {\left|{z}_{1} - {z}_{2}\right|}_\min = 0 at the point of contact.