Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202628 January 2026Morning ShiftMathematicsDefinite IntegrationActual

Let f be a polynomial function such that f (x²+1 )=x⁴+5 x²+2 , for all x R . Then ₀³ f(x) d x is equal to

Options

  1. A5 3
  2. B41 3
  3. C27 2
  4. D33 2

Correct answer

D. 33 2

Step-by-step solution

Let u = x^2 + 1 , then x^2 = u - 1 . Substituting into the given condition: f(u) = (u-1)^2 + 5(u-1) + 2 = u^2 - 2u + 1 + 5u - 5 + 2 = u^2 + 3u - 2 . Therefore, f(x) = x^2 + 3x - 2 . Calculating the integral: ₀^3 f(x)dx = ₀^3 (x^2 + 3x - 2)dx = [ x^3 3 + 3x^2 2 - 2x ]₀^3 = 9 + 27 2 - 6 = 33 2 .

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

The value of the definite integral ₀² 1 3^ x+3 2 , dx is 2026The value of the integral ₀² x(x^2+x+1) ( x+1 )( x^4+x^2+1 ) , dx is equal to: 2026If _ /6 ^ /4 ( (x- 3 ) (x+ 3 )+1 )dx = _e( 3 -1) , then 9 ^2 is equal to ________. 2026Let A = bmatrix 1 & 3 & -1 2 & 1 & 0 & 1 & -1 bmatrix be a singular matrix. Let f(x) = ₀^x (t^2 + 2t + 3) ,dt , x [1, ] . If M and m are respectively the maximum and the minimum va 2026Let f: R R be such that f(xy) = f(x)f(y) , for all x, y R and f(0) 0 . Let g: [1, ) R be a differentiable function such that x^2 g(x) = ₁^x (t^2 f(t) - tg(t)) ,dt . Then g(2) is eq 2026The value of the integral _ -1 ¹ ( x^3 + |x| + 1 x^2 + 2|x| + 1 ) dx is equal to : 2026The value of the integral _ - /4 ^ /4 ( 32 ^4 x 1 + e^ x )dx is: 2026Let (2^ 1-a + 2^ 1+a ) , f(a) , (3^a + 3^ -a ) be in A.P. and be the minimum value of f(a) . Then the value of the integral _ _e( -1) ^ _e( ) dx (e^ 2x - e^ -2x ) is : 2026 Full Definite Integration list All JEE Main PYQs