JEE Main202529 Jan 2025Morning ShiftMathematicsDefinite IntegrationActual
The integral (80 ₀^ 4 ( + 9+16 2 ) d ) is equal to :
Options
- A(3 _e 4 )
- B(4 _ e 3 )
- C(6 _e 4 )
- D(2 _e 3 )
Correct answer
B. (4 _ e 3 )
Step-by-step solution
aligned & I= ₀^ 4 ( + 9-16 2 ) d & Take - =t & ( + ) d =d t & ( - )^2=t^2 & 2 =1-t^2 & =0 t=-1 & = 4 t=0 & I= _ -1 ^0 d t 9+16 (1-t^2 ) & = 1 16 _ -1 ^0 d t 25 16 16 -t^2 & = 1 4 [ 1 10 _ , 5+4 t . ^ 5-4 t ]_ -1 ^0 & = 1 40 [0+ _e 9 ] & I= _e 9 40 & 80 I=2 _e 9 & 80 I=4 _e 3 aligned