JEE Main20249 Apr 2024Evening ShiftMathematicsDefinite IntegrationActual
The value of the integral _ -1 ^2 _e (x+ x^2+1 ) d x is
Options
- A5 - 2 + _e ( 7+4 5 1+ 2 )
- B5 - 2 + _e ( 9+4 5 1+ 2 )
- C2 - 5 + _e ( 7+4 5 1+ 2 )
- D2 - 5 + _e ( 9+4 5 1+ 2 )
Correct answer
D. 2 - 5 + _e ( 9+4 5 1+ 2 )
Step-by-step solution
aligned & I= _ -1 ^2 _e (x+ x^2+1 ) d x & =x _e (x+ x^2+1 )- _ -1 ^2 ( 1+ x x^2+1 x+ x^2+1 ) d x & =x _e (x+ x^2+1 )- _ -1 ^2 x x^2+1 d x aligned aligned & =x _e (x+ x^2+1 )- . x^2+1 |_ -1 ^2 & = (2 _e(2+ 5 )- 5 ) & - (- _e(-1+ 2 )- 2 ) & = _e(2+ 5 )^2- 5 + _e( 2 -1)+ 2 & = _e(2+ 5 )^2- 5 + _e( 2 -1)+ 2 aligned aligned & = 2 - 5 + _e ( (2+ 5 )^2 2+1 ) & = 2 - 5 + _e ( 9+4 5 2+1 ) aligned