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JEE Main 20246 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
6 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Definite Integration

JEE Main 2024 · 6 April · Morning Shift · Mathematics · Definite Integration

∫_0^ π / 4 ( ^2 x ^2 x)/(( ^3 x+ ^3 x)^2) d x is equal to

∫0π/4cos⁡2xsin⁡2x(cos⁡3x+sin⁡3x)2dx\int_0^{\pi / 4} \frac{\cos ^2 x \sin ^2 x}{\left(\cos ^3 x+\sin ^3 x\right)^2} d x is equal to

Options

  1. A1/61 / 6
  2. B1/31 / 3
  3. C1/121 / 12
  4. D1/91 / 9

Correct answer

A. 1/61 / 6

Step-by-step solution

Divide Nr&Dr\mathrm{Nr} \& \mathrm{Dr} by cos⁡x∫0π/4tan⁡2xsec⁡2xdx(1+tan⁡3x)2dx\cos \mathrm{x} \int_0^{\pi / 4} \frac{\tan ^2 x \sec ^2 x d x}{\left(1+\tan ^3 x\right)^2} d x
Let 1+tan⁡31+\tan ^3\mathrm{x}=\mathrm{t}tan⁡2xsec⁡2xdx=dt313∫12dtt2=16\begin{aligned} & \tan ^2 x \sec ^2 x d x=\frac{d t}{3} \\ & \frac{1}{3} \int_1^2 \frac{\mathrm{dt}}{\mathrm{t}^2}=\frac{1}{6} \end{aligned}$$
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