JEE Main 20245 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 5 April
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Definite Integration
JEE Main 2024 · 5 April · Morning Shift · Mathematics · Definite Integration
The integral ∫_0^ π / 4 (136 x)/(3 x+5 x) d x is equal to :
The integral
∫0π/43sinx+5cosx136sinxdx is equal to :
Options
- A3π−50loge2+20loge5
- B3π−25loge2+10loge5
- C3π−10loge(22)+10loge5
- D3π−30loge2+20loge5
Correct answer
A. 3π−50loge2+20loge5
Step-by-step solution
I=∫0π/43sinx+5cosx136sinxdx136sinx=A(3sinx+5cosx)+B(3cosx−5sinx)136=3A−5B...(i)0=5A+3B...(ii)3 B=−5 A⇒B=−35 A136=3 A−5(−35 A)136=3 A+325 A136=334 A⇒A=34136×3=12 B=3−5(12)=−20 I=∫0π/43sinx+5cosxA(3sinx+5cosx)+∫0π/43sinx+5cosxB(3cosx−5sinx)=A(x)0π/4+B[ln(3sinx+5cosx)]0π/4=12(4π)−20ln(23+25)−ln(0+5)=3π−20ln42+20ln5=3π−20×25ln2+20ln5=3π−50ln2+20ln5$
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