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JEE Main20244 Apr 2024Morning ShiftMathematicsDefinite IntegrationActual

Let f(x)= array lr -2, & -2 x 0 x-2, & 0 < x 2 array . and h(x)=f(|x|)+|f(x)| . Then _ -2 ^2 h(x) d x is equal to :

Options

  1. A1
  2. B6
  3. C4
  4. D2

Correct answer

D. 2

Step-by-step solution

h(x)= array cc x-2+2-x=0, & 0 x 2 -x-2+2=-x & -2 x ₀^2 ~h ( x ) dx =0 and _ -2 ^0 ~h ( x ) dx =2

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