JEE Main202127 Aug 2021Morning ShiftMathematicsDefinite IntegrationActual
∫ 6 16 log e x 2 log e x 2 + log e x 2 - 44 x + 484 d x is equal to
Options
- A5
- B10
- C8
- D6
Correct answer
A. 5
Step-by-step solution
Let ∫ 6 16 log e x 2                                     d x log e x 2 + log e x 2 - 44 x + 484 ∫ 6 16 log e x 2 log e x 2 + log e x - 22 2 d x             . . . . . ( 1 ) We know ∫ a b f x d x = ∫ a b f a + b - x d x So, ∫ 6 16 log e 22 - x 2 log e 22 - x 2 + log e 22 - 22 - x 2 d x I = ∫ 6 16 log e 22 - x 2 log e x 2 + log e 22 - x 2 dx       &#