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JEE Main202125 Feb 2021Evening ShiftMathematicsDefinite IntegrationActual

The value of ∫ - 2 2 3 x 2 - 3 x - 6 d x is

Correct answer

0

Step-by-step solution

∫ - 2 2 3 x 2 - x - 2 d x = 3 ∫ - 2 2 x 2 - x - 2 d x = 3 ∫ - 2 - 1 x 2 - x - 2 d x + ∫ - 1 2 - x 2 - x - 2 d x = 3 x 3 3 - x 2 2 - 2 x - 2 - 1 - x 3 3 - x 2 2 - 2 x - 1 2 = 3 7 - 2 3 = 19

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