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JEE Main20209 Jan 2020Morning ShiftMathematicsDefinite IntegrationActual

The value of ∫ 0 2 π x sin 8 ⁡ x sin 8 ⁡ x + cos 8 ⁡ x d x is equal to:

Options

  1. A2 π
  2. B2 π 2
  3. Cπ 2
  4. D4 π

Correct answer

C. π 2

Step-by-step solution

Given, I = ∫ 0 2 π x sin 8 ⁡ x sin 8 ⁡ x + cos 8 ⁡ x d x     . . . i Use the property ∫ a b f x d x = ∫ a b f a + b - x d x we get, I = ∫ 0 2 π 2 π - x sin 8 ⁡ 2 π - x sin 8 ⁡ 2 π - x + cos 8 ⁡ 2 π - x d x = ∫ 0 2 π 2 π - x sin 8 ⁡ x sin 8 ⁡ x + cos 8 ⁡ x d x     . . . i i Adding equation i   &   i i   we get, 2 I = ∫ 0 2 π 2 π sin 8 &#828

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