JEE Main201910 Jan 2019Evening ShiftMathematicsDefinite IntegrationActual
If ∫ 0 x f t d t = x 2 + ∫ x 1 t 2 f t d t , then f ' 1 2 is
Options
- A18 25
- B24 25
- C4 5
- D6 25
Correct answer
B. 24 25
Step-by-step solution
Differentiating both the sides w.r.t. x f x = 2 x - x 2 f x ⇒ f x = 2 x 1 + x 2 ⇒ f ' x = 1 + x 2 × 2 - 2 x × 2 x 1 + x 2 2 = 2 - 2 x 2 1 + x 2 2 Hence, f ' 1 2 = 24 25