Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main201815 Apr 2018Evening ShiftMathematicsDefinite IntegrationActual

The value of integral _ 4 ^ 3 4 x 1+ x d x is

Options

  1. A2 ( 2 +1)
  2. B( 2 -1)
  3. C2 ( 2 -1)
  4. D2

Correct answer

A. 2 ( 2 +1)

Step-by-step solution

Let I= _ 4 ^ 3 4 x 1+ x d x also let K= x 1+ x Multiplying numerator and denominator by (1- x) , we get; aligned K &= x(1- x) 1-( x)^2 = x(1- x) ( x)^2 &=x(1- x) ^2 x &=x ^2 x-x x ^2 x=x ^2 x-x x & x aligned Now, I= _ 4 ^ 3 4 x ^2 x d x- _ 4 ^ 3 4 x x x d x = [x x- d x d x x d x ]_ 4 ^ 3 4 - [x x- d x d x x d x ]_ 4 ^ 3 4 aligned &=[x x- | x|]_ 4 ^ 3 4 &-[x x- | x+ x|]_ 4 ^ 3 4 +c & I= [ 3 4 3 4 - | 3 4 | . . & .- [ 3 4 3 4 - | 3 4 + 3 4 | ] &- [ 4 4 - | 4 | . . & .- [ 4 4 - | 4 + 4 | ] &= 2 ( 2 +1) aligned

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

The value of the definite integral ₀² 1 3^ x+3 2 , dx is 2026The value of the integral ₀² x(x^2+x+1) ( x+1 )( x^4+x^2+1 ) , dx is equal to: 2026If _ /6 ^ /4 ( (x- 3 ) (x+ 3 )+1 )dx = _e( 3 -1) , then 9 ^2 is equal to ________. 2026Let A = bmatrix 1 & 3 & -1 2 & 1 & 0 & 1 & -1 bmatrix be a singular matrix. Let f(x) = ₀^x (t^2 + 2t + 3) ,dt , x [1, ] . If M and m are respectively the maximum and the minimum va 2026Let f: R R be such that f(xy) = f(x)f(y) , for all x, y R and f(0) 0 . Let g: [1, ) R be a differentiable function such that x^2 g(x) = ₁^x (t^2 f(t) - tg(t)) ,dt . Then g(2) is eq 2026The value of the integral _ -1 ¹ ( x^3 + |x| + 1 x^2 + 2|x| + 1 ) dx is equal to : 2026The value of the integral _ - /4 ^ /4 ( 32 ^4 x 1 + e^ x )dx is: 2026Let (2^ 1-a + 2^ 1+a ) , f(a) , (3^a + 3^ -a ) be in A.P. and be the minimum value of f(a) . Then the value of the integral _ _e( -1) ^ _e( ) dx (e^ 2x - e^ -2x ) is : 2026 Full Definite Integration list All JEE Main PYQs