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JEE Main2004MathematicsDefinite IntegrationActual

The value of _ -2 ^3 |1-x^2 | d x is

Options

  1. A28 3
  2. B14 3
  3. C7 3
  4. D1 3

Correct answer

A. 28 3

Step-by-step solution

_ -2 ⁻¹ (x^2-1 ) d x+ _ -1 ^1 (1-x^2 ) d x+ ₁^3 (x^2-1 ) d x= x^3 3 - .x |_ -2 ⁻¹+x- . x^3 3 |_ -1 ^1+ x^3 3 - .x |₁ ^3= 28 3

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