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JEE Main 20238 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
8 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2023 · 8 April · Evening Shift · Mathematics · Determinants

Let S be the set of all values of θ ∈ [ - π, π ] for which the...

Let SS be the set of all values of θ∈[−π,π]\theta \in [ - \pi, \pi ] for which the system of linear equations
x+y+3z=0x + y + \sqrt{3}z = 0
−x+(tanθ)y+7z=0- x + ( tan\theta ) y + \sqrt{7}z = 0
x+y+(tanθ)z=0x + y + ( tan\theta ) z = 0
has non-trivial solution.Then 120π∑0∈Sθ\dfrac{120}{\pi}\mathop{∑}_{0 \in S}\theta is equal to

Options

  1. A2020
  2. B4040
  3. C3030
  4. D1010

Correct answer

A. 2020

Step-by-step solution

Given,

SS be the set of all values of θ∈[−π,π]\theta \in [ - \pi, \pi ] for which the system of linear equations
x+y+3z=0x + y + \sqrt{3}z = 0
−x+(tanθ)y+7z=0- x + ( tan\theta ) y + \sqrt{7}z = 0
x+y+(tanθ)z=0x + y + ( tan\theta ) z = 0
has non-trivial solution,

So, by condition of non-trivial solution we get,

\left|\begin{cases}1 & 1 & \sqrt{3} \\ - 1 & tan\theta & \sqrt{7} \\ 1 & 1 & tan\theta\end{cases}\right| = 0

⇒(tan⁡2θ−7)−(−tanθ−7)+3(−1−tanθ)=0⇒ \left(\tan^{2}\theta - \sqrt{7}\right) - \left(- tan\theta - \sqrt{7}\right) + \sqrt{3}\left(- 1 - tan\theta\right) = 0

⇒tan⁡2θ+(1−3)tanθ−3=0⇒ \tan^{2}\theta + \left(1 - \sqrt{3}\right)tan\theta - \sqrt{3} = 0

⇒(tanθ+1)(tanθ−3)=0⇒ \left(tan\theta + 1\right)\left(tan\theta - \sqrt{3}\right) = 0

⇒tanθ=3,−1⇒ tan\theta = \sqrt{3}, - 1

⇒θ=π3,−2π3,−π4,3π4⇒ \theta = \dfrac{\pi}{3}, \dfrac{- 2\pi}{3}, \dfrac{- \pi}{4}, \dfrac{3\pi}{4}

Hence,

120π∑θ=120(13−23−14+34)=20\dfrac{120}{\pi} ∑ \theta = 120\left(\dfrac{1}{3} - \dfrac{2}{3} - \dfrac{1}{4} + \dfrac{3}{4}\right) = 20

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