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JEE Main 202324 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
24 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2023 · 24 January · Morning Shift · Mathematics · Determinants

Let N denote the number that turns up when a fair die is rolled. If...

Let NN denote the number that turns up when a fair die is rolled. If the probability that the system of equations

x+y+z=12x+Ny+2z=23x+3y+Nz=3x + y + z = 12x + Ny + 2z = 23x + 3y + Nz = 3

has unique solution is k6,\dfrac{k}{6}, then the sum of value of kk and all possible values of NN is

Options

  1. A1818
  2. B1919
  3. C2020
  4. D2121

Correct answer

C. 2020

Step-by-step solution

Given equations are

x+y+z=12x+Ny+2z=23x+3y+Nz=3x + y + z = 12x + Ny + 2z = 23x + 3y + Nz = 3

So,

∆ = \left|\begin{cases}1 & 1 & 1 \\ 2 & N & 2 \\ 3 & 3 & N\end{cases}\right|

Applying C2↔C2−C1and{C}_{2} ↔ {C}_{2} - {C}_{1} and{C}_{3} ↔ {C}_{3} - {C}_{1}</p><p></p><p>⇒ ∆ = \left|{1002N−2030N−3\begin{cases}1 & 0 & 0 \\ 2 & N - 2 & 0 \\ 3 & 0 & N - 3\end{cases}\right|</p><p></p><p>⇒ ∆ = \left(N - 2\right)\left(N - 3\right)</p><p>Foruniquesolution</p><p>For unique solution∆ \ne 0,so</p><p>, so</p><p>N \ne 2, 3</p><p>Also,</p><p>Also,N \in \left\{1, 2, 3, 4, 5, 6\right\}andforuniquesolutionand for unique solutionNcantakevalues{1,4,5,6}can take values \left\{1, 4, 5, 6\right\}.

⇒P⇒ P(system has unique solution ) =46=k6= \dfrac{4}{6} = \dfrac{k}{6}

So, k=4k = 4

Therefore, required sum is

=4+1+4+5+6=20= 4 + 1 + 4 + 5 + 6 = 20

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