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JEE Main 202225 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
25 July
Shift
Evening Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2022 · 25 July · Evening Shift · Mathematics · Determinants

The number of real values of λ , such that the system of linear...

The number of real values of λ\lambda, such that the system of linear equations

2x−3y+5z=92x - 3y + 5z = 9

x+3y−z=−18x + 3y - z = - 18

3x−y+(λ2−∣λ∣)z=163x - y + \left({\lambda}^{2} - \left|\lambda\right|\right)z = 16 has no solutions, is

Options

  1. A00
  2. B11
  3. C22
  4. D44

Correct answer

C. 22

Step-by-step solution

For the system of linear equations

2x−3y+5z=92x - 3y + 5z = 9

x+3y−z=−18x + 3y - z = - 18

3x−y+(λ2−∣λ∣)z=163x - y + \left({\lambda}^{2} - \left|\lambda\right|\right)z = 16 to have no solutions,

∆∆ should be equal to 00.

i.e. \Delta = \left|\begin{cases}2 & - 3 & 5 \\ 1 & 3 & - 1 \\ 3 & - 1 & {\lambda}^{2} - \left|\lambda\right|\end{cases}\right|

=2(3λ2−3∣λ∣−1)+3(λ2−∣λ∣+3)+5(−1−9)= 2\left(3{\lambda}^{2} - 3\left|\lambda\right| - 1\right) + 3\left({\lambda}^{2} - \left|\lambda\right| + 3\right) + 5\left(- 1 - 9\right)

=9λ2−9∣λ∣−43= 9{\lambda}^{2} - 9\left|\lambda\right| - 43

=9∣λ∣2−9∣λ∣−43= 9{\left|\lambda\right|}^{2} - 9\left|\lambda\right| - 43

Now ∆=0∆ = 0 for 22 values of \left|\lambda\right|asfortheabovequadraticthevalueofdeterminantisgreaterthanzero.</p><p>So,as for the above quadratic the value of determinant is greater than zero.</p><p>So,2valuesofvalues of\lambda satisfy the system of equations to obtain no solution.

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