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JEE Main 202224 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
24 June
Shift
Morning Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2022 · 24 June · Morning Shift · Mathematics · Determinants

The number of values of α for which the system of equations x + y +...

The number of values of α\alpha for which the system of equations
x+y+z=αx + y + z = \alpha

\alphax+2\alphay+3z=−1\alphax + 2\alphay + 3z = - 1

x+3\alphay+5z=4x + 3\alphay + 5z = 4

is inconsistent, is

Options

  1. A00
  2. B11
  3. C22
  4. D33

Correct answer

B. 11

Step-by-step solution

Given linear equations are

x+y+z=αx + y + z = \alpha

\alphax+2\alphay+3z=−1\alphax + 2\alphay + 3z = - 1

x+3\alphay+5z=4x + 3\alphay + 5z = 4

For this system of linear equations to have inconsistent solution

D = \left|\begin{cases}1 & 1 & 1 \\ \alpha & 2\alpha & 3 \\ 1 & 3\alpha & 5\end{cases}\right| = 0

⇒(α−1)2=0⇒ {\left(\alpha - 1\right)}^{2} = 0

⇒α=1⇒ \alpha = 1

Now for α=1\alpha = 1

{D}_{1} = \left|\begin{cases}1 & 1 & 1 \\ - 1 & 2 & 3 \\ 4 & 3 & 5\end{cases}\right|

=(10−9)−(−5−12)+(−3−8)= \left(10 - 9\right) - \left(- 5 - 12\right) + \left(- 3 - 8\right)

=1+17−11≠0= 1 + 17 - 11 \ne 0

Hence, for α=1\alpha = 1 the system of equation has inconsistent solution.

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