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JEE Main 202125 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
25 February
Shift
Evening Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2021 · 25 February · Evening Shift · Mathematics · Determinants

Let A be a 3 × 3 matrix with det (A) = 4 . Let R _ i denote the i ^...

Let AA be a 3×33 \times 3 matrix with det(A)=4det \left(A\right) = 4. Let Ri{R}_{i} denote the ith{i}^{th} row of AA. If a matrix BB is obtained by performing the operation R2→2R2+5R3{R}_{2} \to 2{R}_{2} + 5{R}_{3} on 2A2A, then det(B)det \left(B\right) is equal to :

Options

  1. A6464
  2. B1616
  3. C128128
  4. D8080

Correct answer

A. 6464

Step-by-step solution

Let A = \left[\begin{cases}{a}_{11} & {a}_{12} & {a}_{13} \\ {a}_{21} & {a}_{22} & {a}_{23} \\ {a}_{31} & {a}_{32} & {a}_{33}\end{cases}\right]⇒ 2A = \left[\begin{cases}2{a}_{11} & 2{a}_{12} & 2{a}_{13} \\ 2{a}_{21} & 2{a}_{22} & 2{a}_{23} \\ 2{a}_{31} & 2{a}_{32} & 2{a}_{33}\end{cases}\right]

R2→2R2+5R3{R}_{2} \to 2{R}_{2} + 5{R}_{3}

B = \left[\begin{cases}2{a}_{11} & 2{a}_{12} & 2{a}_{13} \\ 4{a}_{21} + 10{a}_{31} & 4{a}_{22} + 10{a}_{32} & 4{a}_{23} + 10{a}_{33} \\ 2{a}_{31} & 2{a}_{32} & 2{a}_{33}\end{cases}\right]

\left|B\right| = \left|{2a112a122a134a21+10a314a22+10a324a23+10a332a312a322a33\begin{cases}2{a}_{11} & 2{a}_{12} & 2{a}_{13} \\ 4{a}_{21} + 10{a}_{31} & 4{a}_{22} + 10{a}_{32} & 4{a}_{23} + 10{a}_{33} \\ 2{a}_{31} & 2{a}_{32} & 2{a}_{33}\end{cases}\right|</p><p>\left|B\right| = \left|\begin{cases}2{a}_{11} & 2{a}_{12} & 2{a}_{13} \\ 4{a}_{21} & 4{a}_{22} & 4{a}_{23} \\ 2{a}_{31} & 2{a}_{32} & 2{a}_{33}\end{cases}\right| + \left|\begin{cases}2{a}_{11} & 2{a}_{12} & 2{a}_{13} \\ 10{a}_{31} & 10{a}_{32} & 10{a}_{33} \\ 2{a}_{31} & 2{a}_{32} & 2{a}_{33}\end{cases}\right|

\left|B\right| = 2 \times 4 \times 2\left|{a11a12a13a21a22a23a31a32a33\begin{cases}{a}_{11} & {a}_{12} & {a}_{13} \\ {a}_{21} & {a}_{22} & {a}_{23} \\ {a}_{31} & {a}_{32} & {a}_{33}\end{cases}\right| + 2 \times 10 \times 2\left|{a11a12a13a31a32a33a31a32a33\begin{cases}{a}_{11} & {a}_{12} & {a}_{13} \\ {a}_{31} & {a}_{32} & {a}_{33} \\ {a}_{31} & {a}_{32} & {a}_{33}\end{cases}\right|</p><p>\left|B\right| = 16\left|\begin{cases}{a}_{11} & {a}_{12} & {a}_{13} \\ {a}_{21} & {a}_{22} & {a}_{23} \\ {a}_{31} & {a}_{32} & {a}_{33}\end{cases}\right| + 0

\left|B\right| = 16\left|A\right|</p><p>Valueoftheseconddeterminantiszero.SinceRow</p><p>Value of the second determinant is zero. Since Row2 and Row 33 are identical.

∣B∣=16×4=64(∵∣A∣=4)| B | = 16 \times 4 = 64\left(∵ | A | = 4\right)

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