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JEE Main 202124 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
24 February
Shift
Evening Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2021 · 24 February · Evening Shift · Mathematics · Determinants

Let A and B be 3 × 3 real matrices such that A is a symmetric...

Let AandBA and B be 3×33 \times 3 real matrices such that AA is a symmetric matrix and BB is a skew-symmetric matrix. Then the system of linear equations \left({A}^{2}{B}^{2} - {B}^{2}{A}^{2}\right)X = O,wherewhereXisais a3 \times 1columnmatrixofunknownvariablesandcolumn matrix of unknown variables andOisais a3 \times 1$ null matrix, has

Options

  1. Aexactly two solutions
  2. Binfinitely many solutions
  3. Ca unique solution
  4. Dno solution

Correct answer

B. infinitely many solutions

Step-by-step solution

Let AT=AandBT=−B{A}^{T} = A and {B}^{T} = - B

C=A2B2−B2A2C = {A}^{2}{B}^{2} - {B}^{2}{A}^{2}

CT=(A2B2)T−(B2A2)T{C}^{T} = {\left({A}^{2}{B}^{2}\right)}^{T} - {\left({B}^{2}{A}^{2}\right)}^{T}

=(B2)T(A2)T−(A2)T(B2)T= {\left({B}^{2}\right)}^{T}{\left({A}^{2}\right)}^{T} - {\left({A}^{2}\right)}^{T}{\left({B}^{2}\right)}^{T}

=B2A2−A2B2= {B}^{2}{A}^{2} - {A}^{2}{B}^{2}

CT=−C{C}^{T} = - C

CC is skew symmetric.

So det \left(C\right) = 0$

so system have infinite solutions.

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