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JEE Main 20198 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
8 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2019 · 8 April · Evening Shift · Mathematics · Determinants

Let the numbers 2, b, c be in an A.P. and A = [ cases 1 & 1 & 1 2 &...

Let the numbers 2,b,c2, b, c be in an A.P. and A=A =\left[{1112bc4b2c2\begin{cases}1 & 1 & 1 \\ 2 & b & c \\ 4 & {b}^{2} & {c}^{2}\end{cases}\right].If. Ifdet ( A ) \in [ 2,16 ] , then cc lies in the interval:

Options

  1. A[2,3)\left[2,3\right)
  2. B[4,6]\left[4,6\right]
  3. C[3,2+234]\left[3,2 + {2}^{\dfrac{3}{4}}\right]
  4. D(2+234,4)\left(2 + {2}^{\dfrac{3}{4}}, 4\right)

Correct answer

B. [4,6]\left[4,6\right]

Step-by-step solution

\left|{1112bc4b2c2\begin{cases}1 & 1 & 1 \\ 2 & b & c \\ 4 & {b}^{2} & {c}^{2}\end{cases}\right|\overset{{C}_{2} \to {C}_{2} - {C}_{1}, {C}_{3} \to {C}_{3} - {C}_{1}}{\to}\left|{1002b−2c−24b2−4c2−4\begin{cases}1 & 0 & 0 \\ 2 & b - 2 & c - 2 \\ 4 & {b}^{2} - 4 & {c}^{2} - 4\end{cases}\right| = \left(b - 2\right)\left(c - 2\right)\left(c - b\right)<br/>Letcommondifferenceof<br />Let common difference ofAP = d<br/><br />∴ b = 2 + d, c = 2 + 2d<br/>∣A∣=d×2d×d=2d3∈[2,16]<br />\left|A\right| = d \times 2d \times d = 2{d}^{3} \in \left[2, 16\right]
⇒d3∈[1,8]⇒d∈[1,2]⇒2d∈[2,4]⇒ {d}^{3} \in \left[1, 8\right] ⇒ d \in \left[1, 2\right] ⇒ 2d \in \left[2, 4\right]
⇒2+2d∈[4,6]⇒ 2 + 2d \in \left[4, 6\right]
∴c∈[4,6]∴ c \in \left[4, 6\right]
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