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JEE Main 201912 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
12 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2019 · 12 January · Evening Shift · Mathematics · Determinants

The set of all values of λ for which the system of linear equations...

The set of all values of λ\lambda for which the system of linear equations
x−2y−2z=\lambdaxx - 2y - 2z = \lambdax
x+2y+z=\lambdayx + 2y + z = \lambday
−x−y=\lambdaz- x - y = \lambdaz
has a non-trivial solution :

Options

  1. Ais an empty set
  2. Bcontains more than two elements
  3. Cis a singleton
  4. Dcontains exactly two elements

Correct answer

C. is a singleton

Step-by-step solution

For non-trivial solution, ∆=0∆ = 0.

⇒ \left|\begin{cases}1 - \lambda & - 2 & - 2 \\ 1 & 2 - \lambda & 1 \\ - 1 & - 1 & - \lambda\end{cases}\right| = 0

⇒(1−λ)(−2λ+λ2+1)+1(−λ+1)−1(−1+2−λ)=0⇒ \left(1 - \lambda\right)\left(- 2\lambda + {\lambda}^{2} + 1\right) + 1\left(- \lambda + 1\right) - 1\left(- 1 + 2 - \lambda\right) = 0

⇒λ2−3λ2+3λ−1=0⇒ {\lambda}^{2} - 3{\lambda}^{2} + 3\lambda - 1 = 0

⇒(λ−1)3=0⇒ {\left(\lambda - 1\right)}^{3} = 0

⇒λ=1⇒ \lambda = 1

Singleton set

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