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JEE Main 201910 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
10 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2019 · 10 January · Evening Shift · Mathematics · Determinants

The number of values of θ ∈ (0, π) for which the system of linear...

The number of values of θ∈(0,π)\theta \in \left(0, \pi\right) for which the system of linear equations
x + 3y + 7z = 0<br/><br />- x + 4y + 7z = 0<br/>(sin⁡3θ)x+(cos⁡2θ)y+2z=0<br />\left(\sin 3\theta\right)x + \left(\cos 2\theta\right)y + 2z = 0
has a non-trivial solution, is:

Options

  1. ATwo
  2. BThree
  3. CFour
  4. DOne

Correct answer

A. Two

Step-by-step solution

For non-trivial solutions

\left|\begin{cases}1 & 3 & 7 \\ - 1 & 4 & 7 \\ \sin 3\theta & \cos 2\theta & 2\end{cases}\right| = 0

⇒4sin⁡3θ+4sin⁡2θ−3sinθ=0⇒ 4\sin^{3}\theta + 4\sin^{2}\theta - 3sin\theta = 0

⇒sinθ=0or⇒ sin\theta = 0 orsin\theta = \dfrac{1}{2} or sin\theta = - \dfrac{3}{2}<br/><br/>Since<br /><br />Since\theta \in \left(0, \pi\right)

⇒θ=⇒ \theta =\dfrac{\pi}{6}andand\dfrac{5\pi}{6} will satisfy the equation</p><p>because</p><p>becausesin\theta = - \dfrac{3}{2} isnotpossibleasrangeofs not possible as range ofsin\thetais[−1,1]is \left[- 1, 1\right]

⇒⇒ Number of θ\theta ' s=2s = 2

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