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The number of values of k for which the system of linear equations k + 2 x + 10 y = k & k x + k + 3 y = k - 1 has no solution is

Options

  1. A1
  2. B2
  3. C3
  4. D4

Correct answer

A. 1

Step-by-step solution

For no solution k + 2 k = 10 k + 3 = k k - 1 ⇒ k + 2 k + 3 = 10 k ⇒ k 2 - 5 k + 6 = 0 ⇒ k = 2 ,   3 k ≠ 2 for k = 2 both lines are identical. So, only k = 3 is possible. So the number of values of k is 1 .

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