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JEE Main20244 Apr 2024Morning ShiftMathematicsFunctionsActual

Let the sum of the maximum and the minimum values of the function f(x)= 2 x^2-3 x+8 2 x^2+3 x+8 be m n , where gcd ( m , n )=1 . Then m + n is equal to :

Options

  1. A195
  2. B201
  3. C217
  4. D182

Correct answer

B. 201

Step-by-step solution

aligned & y= 2 x^2-3 x+8 2 x^2+3 x+8 & x^2(2 y-2)+x(3 y+3)+8 y-8=0 & use D 0 & (3 y+3)^2-4(2 y-2)(8 y-8) 0 & (11 y-5)(5 y-11) 0 & y [ 5 11 , 11 5 ] & y=1 is also included aligned

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