JEE Main202325 Jan 2023Morning ShiftMathematicsFunctionsActual
Let f : 0 , 1 → ℝ be a function defined by f x = 1 1 - e - x , and g x = f - x - f x . Consider two statements (I) g is an increasing function in 0 , 1 (II) g is one-one in 0 , 1 Then,
Options
- AOnly (I) is true
- BOnly (II) is true
- CNeither (I) nor (II) is true
- DBoth (I) and (II) are true
Correct answer
D. Both (I) and (II) are true
Step-by-step solution
Given, f : 0 , 1 → ℝ be a function defined by f x = 1 1 - e - x , and g x = f - x - f x Now using g x = f - x - f x we get, g ( x ) = 1 1 - e x - e x e x - 1 ⇒ g x = 1 + e x 1 - e x Now differentiating the above function with respect to x we get, ⇒ g ' x = 2 e x 1 - e x 2 > 0 Since g ' x is always positive So,   g x is one-one in 0 , 1 And g x is increasing in 0 , 1