Two vertical poles A B = 15 m and C D = 10 m are standing apart on a horizontal ground with points A and C on the ground. If P is the point of intersection of B C and A D , then the height of P (in m ) above the line A C is :

Step-by-step solution

Δ A Q P ~ Δ A C D ⇒ x h = x + y 10       . . . 1 ∵ Δ C Q P ~ Δ C A B ⇒ y h = x + y 15       . . . . 2 Adding 1   &   2 , we get x + y h = x + y 1 10 + 1 15 ⇒ h = 6 .