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JEE Main 20204 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
4 September
Shift
Morning Shift
Subject
Mathematics
Chapter
Heights and Distances

JEE Main 2020 · 4 September · Morning Shift · Mathematics · Heights and Distances

Two vertical poles AB = 15m and CD = 10m are standing apart on a...

Two vertical poles AB=15mAB = 15m and CD=10mCD = 10m are standing apart on a horizontal ground with points AA and CC on the ground. If PP is the point of intersection of BCBC and AD,AD, then the height of PP (in mm ) above the line ACAC is :Two vertical poles AB = 15m and CD = 10m are standing apart on a horizontal ground with points A and C on the ground.

Options

  1. A20/320 / 3
  2. B55
  3. C10/310 / 3
  4. D66

Correct answer

D. 66

Step-by-step solution

Two vertical poles AB = 15m and CD = 10m are standing apart on a horizontal ground with points A and C on the ground.

δAQP δACD\delta AQP ~ \delta ACD

⇒⇒ xh=x+y10...(1)\dfrac{x}{h} = \dfrac{x + y}{10} . . . \left(1\right)

∵∵ δCQP δCAB\delta CQP ~ \delta CAB

⇒yh=x+y15....(2)⇒ \dfrac{y}{h} = \dfrac{x + y}{15} . . . . \left(2\right)

Adding \left(1\right) \text{ and } \left(2\right),weget</p><p>, we get</p><p>\dfrac{x + y}{h} = \left(x + y\right)\left(\dfrac{1}{10} + \dfrac{1}{15}\right)</p><p></p><p>⇒ h = 6.

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