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JEE Main 2007
Exam
JEE Main
Year
2007
Subject
Mathematics
Chapter
Heights and Distances

JEE Main 2007 · Mathematics · Heights and Distances

A tower stands at the centre of a circular park. A and B are two...

A tower stands at the centre of a circular park. AA and BB are two points on the boundary of the park such that AB(=a)A B(=a) subtends an angle of 60∘60^{\circ} at the foot of the tower, and the angle of elevation of the top of the tower from AA or BB is 30∘30^{\circ}. The height of the tower isA tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that A B(=a)

Options

  1. A2a3\frac{2 a}{\sqrt{3}}
  2. B2a32 a \sqrt{3}
  3. Ca3\frac{a}{\sqrt{3}}
  4. Da3a \sqrt{3}

Correct answer

C. a3\frac{a}{\sqrt{3}}

Step-by-step solution

△\triangleOAB\mathrm{O A B}isequilateralis equilateral\therefore OA=\mathrm{OA}=\mathrm{OB}=\mathrm{AB}==a\mathrm{a} Now tan⁡30∘=ha∴h=a3\tan 30^{\circ}=\frac{h}{a} \therefore h=\frac{a}{\sqrt{3}}. \text{. }<imgsrc="https://cdn−question−pool.getmarks.app/pyq/jeemain/IR1Oldzf51bmUBbNx7bW1jyaoIVgv2SQsPGml3z6Vg.original.fullsize.png"><br><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_main/IR1Oldz_f51bmUBbNx7bW1jyaoIVgv2SQsPGml3z6Vg.original.fullsize.png"><br>
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