JEE Main2007MathematicsHeights and DistancesActual
A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that A B(=a) subtends an angle of 60^ at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30^ . The height of the tower is
Options
- A2 a 3
- B2 a 3
- Ca 3
- Da 3
Correct answer
C. a 3
Step-by-step solution
O A B is equilateral OA = OB = AB = a Now 30^ = h a h= a 3 .