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JEE Main 202311 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Hyperbola

JEE Main 2023 · 11 April · Morning Shift · Mathematics · Hyperbola

Let R be a rectangle given by the lines x = 0, x = 2 , y = 0 and y...

Let RbearectanglegivenbythelinesR be a rectangle given by the linesx = 0, x = 2,,y = 0andandy = 5.Let. LetA(α,0)A\left(\alpha, 0\right) and B(0,β),α∈[0,2]B\left(0, \beta\right), \alpha \in \left[0, 2\right] and β∈[0,5]\beta \in \left[0, 5\right], be such that the line segment ABAB divides the area of the rectangle RR in the ratio 4:14: 1. Then, the mid-point of ABAB lies on aLet R be a rectangle given by the lines x = 0, x = 2 , y = 0 and y = 5 . Let A(α, 0) and B(0, β), α ∈ [0, 2] and β ∈

Options

  1. Astraight line
  2. Bparabola
  3. Chyperbola
  4. Dcircle

Correct answer

C. hyperbola

Step-by-step solution

Given,

RR be a rectangle given by the lines x=0,x=2x = 0, x = 2, y=0andy=5y = 0 and y = 5

And point A \left(\alpha, 0\right)andB(0,β)and B \left(0, \beta\right), \alpha \in \left[0, 2\right]andβ∈[0,5]and \beta \in \left[0, 5\right],

Now plotting the diagram we get,

Let R be a rectangle given by the lines x = 0, x = 2 , y = 0 and y = 5 . Let A(α, 0) and B(0, β), α ∈ [0, 2] and β ∈

Now given that line segment ABAB divides the ratio of area in 4:14: 1, we get

\dfrac{10 - \dfrac{1}{2}\alpha\beta}{\dfrac{1}{2}\alpha\beta} = \dfrac{4}{1}</p><p>⇒ 20 - \alpha\beta = 4\alpha\beta</p><p></p><p>⇒ \alpha\beta = 4 . . . . . . \left(1\right)</p><p>Nowusingmidpointformulaweget,</p><p></p><p>Now using midpoint formula we get,</p><p>h = \dfrac{\alpha}{2}\text{andand} \beta =\dfrac{k}{2}</p><p>Nowusingequation(1)</p><p>Now using equation \left(1\right) we get,

⇒4hk=4⇒ 4hk = 4

⇒xy=1⇒ xy = 1 which is a equation of rectangular hyperbola.

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