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JEE Main 201911 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
11 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Hyperbola

JEE Main 2019 · 11 January · Evening Shift · Mathematics · Hyperbola

If a hyperbola has length of its conjugate axis equal to 5 and the...

If a hyperbola has length of its conjugate axis equal to 5 and the distance between its foci is 13 , then the eccentricity of the hyperbola is:

Options

  1. A1312\frac{13}{12}
  2. B2
  3. C136\frac{13}{6}
  4. D138\frac{13}{8}

Correct answer

A. 1312\frac{13}{12}

Step-by-step solution

∴\therefore Conjugate axis =5=5 ∴2b=5\therefore 2 b=5 Distance betwecn foci =13=13 2ae=132 a e=13 Then, b2=a2(e2−1)b^{2}=a^{2}\left(e^{2}-1\right)\Rightarrow a^{2}=36 \therefore a=6 a e=\frac{13}{2} \Rightarrow e=\frac{13}{12}
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