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JEE Main 2005
Exam
JEE Main
Year
2005
Subject
Mathematics
Chapter
Hyperbola

JEE Main 2005 · Mathematics · Hyperbola

The locus of a point P(α, β) moving under the condition that the...

The locus of a point P(α,β)P(\alpha, \beta) moving under the condition that the line y=αx+βy=\alpha x+\beta is a tangent to the hyperbola x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1 is

Options

  1. Aan ellipse
  2. Ba circle
  3. Ca parabola
  4. Da hyperbola

Correct answer

D. a hyperbola

Step-by-step solution

Tangent to the hyperbola x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1 is y=mx±a2m2−b2y=m x \pm \sqrt{a^2 m^2-b^2} Given that y=αx+βy=\alpha x+\beta is the tangent of hyperbola ⇒m=α\Rightarrow m=\alpha and a2m2−b2=β2a^2 m^2-b^2=\beta^2 ∴a2α2−b2=β2\therefore \mathrm{a}^2 \alpha^2-\mathrm{b}^2=\beta^2 Locus is a2x2−y2=b2a^2 x^2-y^2=b^2 which is hyperbola.
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