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JEE Main202118 Mar 2021Morning ShiftMathematicsIndefinite IntegrationActual

If f x = ∫ 5 x 8 + 7 x 6 x 2 + 1 + 2 x 7 2 d x ,   x ≥ 0 ,   f 0 = 0 and f 1 = 1 K , then the value of K is

Correct answer

0

Step-by-step solution

f x = ∫ 5 x 8 + 7 x 6 d x x 14 x - 5 + x - 7 + 2 2 Let x - 5 + x - 7 + 2 = t - 5 x - 6 - 7 x - 8 d x = d t ⇒ f x = ∫ - d t t 2 = 1 t + c f x = x 7 x 2 + 1 + 2 x 7 f 1 = 1 4

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