JEE Main202229 Jun 2022Evening ShiftMathematicsMatricesActual
Let A = 2 - 1 0 2 . If B = I - C 1 5 adj A + C 2 5 ( adj A ) 2 - . . . - C 5 5 ( adj A ) 5 , then the sum of all elements of the matrix B is:
Options
- A- 5
- B- 6
- C- 7
- D- 8
Correct answer
C. - 7
Step-by-step solution
Simplifying the given expression we get, B = I - C 1 5 adj ( A ) + C 2 5 ( adj ( A ) ) 2 - C 3 5 ( adj ( A ) ) 3 + C 4 5 ( adj ( A ) ) 4 - C 5 5 ( adj ( A ) ) 5 ⇒   B = ( I - adj ( A ) ) 5 Now, A = 2 - 1 0 2 ⇒ adj A = 2 1 0 2 So,   B = - 1 - 1 0 - 1 5 ⇒   - B = 1 1 0 1 5 = 1 5 0 1   ⇒ B = - 1 - 5 0 - 1 Now, sum of elements of matrix B = - 1 - 5 - 1 = - 7