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JEE Main 202127 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
27 July
Shift
Evening Shift
Subject
Mathematics
Chapter
Matrices

JEE Main 2021 · 27 July · Evening Shift · Mathematics · Matrices

Let A and B be two 3 × 3 real matrices such that ( A ^ 2 - B ^ 2 )...

Let AandBA and B be two 3×33 \times 3 real matrices such that (A2−B2)\left({A}^{2} - {B}^{2}\right) is invertible matrix. If A5=B5andA3B2=A2B3,{A}^{5} = {B}^{5} and {A}^{3}{B}^{2} = {A}^{2}{B}^{3}, then the value of the determinant of the matrix A3+B3{A}^{3} + {B}^{3} is equal to :

Options

  1. A22
  2. B44
  3. C11
  4. D00

Correct answer

D. 00

Step-by-step solution

Let C=A2−B2;∣C∣≠0C = {A}^{2} - {B}^{2}; \left|C\right| \ne 0

and A5=B5...(1){A}^{5} = {B}^{5} . . . \left(1\right)

A3B2=A2B3...(2)</p><p>Subtractingequation(2){A}^{3}{B}^{2} = {A}^{2}{B}^{3} . . . \left(2\right)</p><p>Subtracting equation \left(2\right) from \left(1\right), we getA5−A3B2=B5−A2B3{A}^{5} - {A}^{3}{B}^{2} = {B}^{5} - {A}^{2}{B}^{3}

⇒A3(A2−B2)⇒ {A}^{3}\left({A}^{2} - {B}^{2}\right) + {B}^{3}\left({A}^{2} - {B}^{2}\right)=O= O

Post multiplying inverse of A2−B2:{A}^{2} - {B}^{2}:

A3+B3=O⇒∣A3+B3∣{A}^{3} + {B}^{3} = O ⇒ \left|{A}^{3} + {B}^{3}\right| = 0</p></p>

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