JEE Main 20207 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2020
- Date
- 7 January
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Matrices
JEE Main 2020 · 7 January · Morning Shift · Mathematics · Matrices
Let α be a root of the equation x ^ 2 + x + 1 = 0 and the matrix A...
Let be a root of the equation and the matrix \left[\right],{A}^{31} is equal to
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Here, where is complex cube root of unity.
{A}^{2} = \dfrac{1}{3}\left[\begin{cases}1 & 1 & 1 \\ 1 & \omega & {\omega}^{2} \\ 1 & {\omega}^{2} & \omega\end{cases}\right]\left[\begin{cases}1 & 1 & 1 \\ 1 & \omega & {\omega}^{2} \\ 1 & {\omega}^{2} & \omega\end{cases}\right] = \left[\begin{cases}1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0\end{cases}\right]
⇒ {A}^{4} = \left[\begin{cases}1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0\end{cases}\right]\left[\begin{cases}1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0\end{cases}\right] = \left[\begin{cases}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{cases}\right]