JEE Main20199 Jan 2019Morning ShiftMathematicsMatricesActual
If A = c o s θ - s i n θ s i n θ c o s θ , then the matrix A - 50 when θ = π 12 , is equal to:
Options
- A3 2 1 2 - 1 2 3 2
- B1 2 3 2 - 3 2 1 2
- C3 2 - 1 2 1 2 3 2
- D1 2 - 3 2 3 2 1 2
Correct answer
A. 3 2 1 2 - 1 2 3 2
Step-by-step solution
A = c o s θ - s i n θ s i n θ c o s θ ⇒ A = c o s θ - s i n θ s i n θ c o s θ = c o s 2 θ + s i n 2 θ = 1 And a d j A = c o s θ s i n θ - s i n θ c o s θ ⇒ A - 1 = 1 A a d j A = c o s θ s i n θ - s i n θ c o s θ ⇒ A - 2 = A - 1 2 = A - 1 A - 1 = c o s θ s i n θ - s i n θ c o s θ c o s θ s i n θ - s i n θ c o s θ = c o s 2 θ - s i n 2 θ 2 s i n θ c o s θ - 2 s i n θ c o s θ c o s 2 θ - s i n 2 θ = c o s 2 θ s i n 2 θ - s i n 2 θ c o s 2 θ It is visible that A - 1 n = c o s n θ s i n n θ - s i n n θ c o s n θ ⇒ A - 5