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JEE Main 20257 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Parabola

JEE Main 2025 · 7 April · Morning Shift · Mathematics · Parabola

Let P be the parabola, whose focus is (-2,1) and directrix is 2...

Let P be the parabola, whose focus is (−2,1)(-2,1) and directrix is 2x+y+2=02 x+y+2=0. Then the sum of the ordinates of the points on P , whose abscissa is -2 , isLet P be the parabola, whose focus is (-2,1) and directrix is 2 x+y+2=0 . Then the sum of the ordinates of the points

Options

  1. A32\frac{3}{2}
  2. B52\frac{5}{2}
  3. C14\frac{1}{4}
  4. D34\frac{3}{4}

Correct answer

A. 32\frac{3}{2}

Step-by-step solution

Equation of parabola
(x+2)2+(y−1)2=(2x+y+25)2<br/><imgsrc="https://cdn−question−pool.getmarks.app/pyq/jeemain/qZ3Y8sfiWupYB2A7M7C8hxcWRQvBpUEFE3t7VgevHOM.original.fullsize.png"/><br/>(x+2)^2+(y-1)^2=\left(\frac{2 x+y+2}{\sqrt{5}}\right)^2<br/><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_main/qZ3Y8sfiWupYB2A7M7C8hxcWRQvBpUEFE3t7VgevHOM.original.fullsize.png"/><br/>5\left[(x+2)^2+(y-1)^2\right]=(2 x+y+2)^2<br/>Put<br/>Putx=-2,5(y-1)^2=(y-2)^2<br/><br/><br/>5(y2−2y+1)=y2−4y+4⇒4y2−6y+1=0⇒y1+y2=32<br/>\begin{aligned}<br/>& 5\left(y^2-2 y+1\right)=y^2-4 y+4 \\ & \Rightarrow 4 y^2-6 y+1=0 \Rightarrow y_1+y_2=\frac{3}{2}<br/>\end{aligned}$
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