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JEE Main 202523 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
23 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Parabola

JEE Main 2025 · 23 January · Morning Shift · Mathematics · Parabola

If the line 3 x-2 y+12=0 intersects the parabola 4 y=3 x^2 at the...

If the line 3x−2y+12=03 x-2 y+12=0 intersects the parabola 4y=3x24 y=3 x^2 at the points AA and BB, then at the vertex of the parabola, the line segment ABA B subtends an angle equal to

Options

  1. Atan⁡−1(45)\tan ^{-1}\left(\frac{4}{5}\right)
  2. Btan⁡−1(97)\tan ^{-1}\left(\frac{9}{7}\right)
  3. Ctan⁡−1(119)\tan ^{-1}\left(\frac{11}{9}\right)
  4. Dπ2−tan⁡−1(32)\frac{\pi}{2}-\tan ^{-1}\left(\frac{3}{2}\right)

Correct answer

B. tan⁡−1(97)\tan ^{-1}\left(\frac{9}{7}\right)

Step-by-step solution

3x−2y+12=04y=3x2∴2(3x+12)=3x2⇒x2−2x−8=0⇒x=−2,4mOA=−3/2,mOB=3tan⁡θ=(−32−31−92)=97θ=tan⁡−1(97) (angle will be acute) \begin{aligned} & 3 x-2 y+12=0 \\ & 4 y=3 x^2 \\ & \therefore 2(3 x+12)=3 x^2 \\ & \Rightarrow x^2-2 x-8=0 \\ & \Rightarrow x=-2,4 \\ & \mathrm{ m}_{\mathrm{OA}}=-3 / 2, \mathrm{ m}_{\mathrm{OB}}=3 \\ & \tan \theta=\left(\frac{\frac{-3}{2}-3}{1-\frac{9}{2}}\right)=\frac{9}{7} \\ & \theta=\tan ^{-1}\left(\frac{9}{7}\right) \text{ (angle will be acute) }\end{aligned}
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