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JEE Main20245 Apr 2024Evening ShiftMathematicsParabolaActual

Let a line perpendicular to the line 2 x-y=10 touch the parabola y^2=4(x-9) at the point P . The distance of the point P from the centre of the circle x^2+y^2-14 x-8 y+56=0 is __________

Correct answer

0

Step-by-step solution

y^2=4(x-9) slope of tangent = -1 2 Point of contact P (9+ 1 (- 1 2 )^2 , 2 1 -1 2 ) aligned & P(13,-4) & center of circle C(7,4) & distance C P= (13-7)^2+(-4-4)^2 & =10 aligned

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