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JEE Main 202229 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
29 June
Shift
Evening Shift
Subject
Mathematics
Chapter
Parabola

JEE Main 2022 · 29 June · Evening Shift · Mathematics · Parabola

Let P: y ^ 2 = 4ax, a > 0 be a parabola with focus S .Let the...

Let P:y2=4ax,a>0P: {y}^{2} = 4ax, a > 0 be a parabola with focus SS.Let the tangents to the parabola PP make an angle of π4\dfrac{\pi}{4} with the line y=3x+5y = 3x + 5 touch the parabola PP at AA and BB. Then the value of aa for which A,BA, B and SS are collinear is:Let P: y ^ 2 = 4ax, a > 0 be a parabola with focus S .Let the tangents to the parabola P make an angle of (π)/(4) with

Options

  1. A88 only
  2. B22 only
  3. C14\dfrac{1}{4}only
  4. Dany a>0a > 0

Correct answer

D. any a>0a > 0

Step-by-step solution

Lines making angle π4\dfrac{\pi}{4} with y=3x+5y = 3x + 5

So using formula tanα=m2−m11+m1m2tan\alpha = \dfrac{{m}_{2} - {m}_{1}}{1 + {m}_{1}{m}_{2}}, we have slope −2 and 12- 2 \text{ and } \dfrac{1}{2}.

Which are perpendicular to each-other so, A,S,BA, S, Bare collinear for all a>0a > 0. (by property that perpendicular tangents will lie on directrix and chord of contact will pass through focus, so the points are collinear )

Let P: y ^ 2 = 4ax, a > 0 be a parabola with focus S .Let the tangents to the parabola P make an angle of (π)/(4) with

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