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JEE Main 20208 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
8 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Parabola

JEE Main 2020 · 8 January · Morning Shift · Mathematics · Parabola

The locus of a point which divides the line segment joining the...

The locus of a point which divides the line segment joining the point (0,−1)\left(0, - 1\right) and a point on the parabola x2=4y{x}^{2} = 4y internally in the ratio 1:21: 2 is:

Options

  1. A9x2−12y=89{x}^{2} - 12y = 8
  2. B9x2−3y=29{x}^{2} - 3y = 2
  3. Cx2−3y=2{x}^{2} - 3y = 2
  4. D4x2−3y=24{x}^{2} - 3y = 2

Correct answer

A. 9x2−12y=89{x}^{2} - 12y = 8

Step-by-step solution

Let point PP be \left(2t, {t}^{2}\right)andQbe(h,k)and Q be \left(h, k\right) .
h=2t3,k=−2+t23h = \dfrac{2t}{3}, k = \dfrac{- 2 + {t}^{2}}{3}
Hence, locus is 3k+2=(3h2)s2⇒9x2=12y+83k + 2 = {\left(\dfrac{3h}{2}\right)s}^{2} ⇒ 9{x}^{2} = 12y + 8
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