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JEE Main201911 Jan 2019Evening ShiftMathematicsParabolaActual

If the area of the triangle whose one vertex is at the vertex of the parabola, y²+4 (x-a² )=0 and the other two vertices are the points of intersection of the parabola and y -axis, is 250 sq. units, then a value of 'a' is :

Options

  1. A5 5
  2. B5 (2^ 1 / 3 )
  3. C(10)³³
  4. D5

Correct answer

D. 5

Step-by-step solution

y^ t =-4 (x-a² ) Area = 1 2 (4 a) (a² )=2 a³ Since 2 a³=250 a=5

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