JEE Main2012MathematicsParabolaActual
The equation of the normal to the parabola, x^2=8 y at x=4 is
Options
- Ax+2 y=0
- Bx+y=2
- Cx-2 y=0
- Dx+y=6
Correct answer
D. x+y=6
Step-by-step solution
x^2=8 y When, x=4 , then y=2 Now . d y d x = 2 x 8 = x 4 , d y d x ]_ x=4 =1 Slope of normal =- 1 d y d x =-1 Euqation of normal at x=4 is y-2=-1(x-4) y=-x+4+2=-x+6 x+y=6