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JEE Main 2006
Exam
JEE Main
Year
2006
Subject
Mathematics
Chapter
Parabola

JEE Main 2006 · Mathematics · Parabola

Angle between the tangents to the curve y=x^2-5 x+6 at the points...

Angle between the tangents to the curve y=x2−5x+6y=x^2-5 x+6 at the points (2,0)(2,0) and (3,0)(3,0) is

Options

  1. Aπ2\frac{\pi}{2}
  2. Bπ2\frac{\pi}{2}
  3. Cπ6\frac{\pi}{6}
  4. Dπ4\frac{\pi}{4}

Correct answer

B. π2\frac{\pi}{2}

Step-by-step solution

dydx=2x−5\frac{d y}{d x}=2 x-5 ∴m1=(2x−5)(2,0)=−1,m2=(2x−5)(3,0)=1\therefore m_1=(2 x-5)_{(2,0)}=-1, m_2=(2 x-5)_{(3,0)}=1 ⇒m1m2=−1\Rightarrow m_1 m_2=-1
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