Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202329 Jan 2023Evening ShiftMathematicsSequences and SeriesActual

The number of 3 digit numbers, that are divisible by either 3 or 4 but not divisible by 48 , is

Options

  1. A472
  2. B432
  3. C507
  4. D400

Correct answer

B. 432

Step-by-step solution

We know that, Total number of three digit number will be 999 - 99 = 900 , Now, Number of 3 - digit number which are divisible by 3 will be 900 3 = 300 , Number of 3 - digit number which are divisible by 4 will be 900 4 = 225 , Number of 3 - digit number which are divisible by 3   &   4 both will be 900 12 = 75 , So , number of 3 - digit number which are divisible by 3   or   4 will be 300 + 225 - 75 = 450 , Now, number of 3 - digit number which are divisible by 48 is 900 48 = 18 So, number o

Practice Sequences and Series on Quantrex Academy →

More from Sequences and Series

Let = 3+4+8+9+13+14+ upto 40 terms. If ( )^ 1020 is a root of the equation x^2+x-2=0 , (0, 2 ) , then ^2 + 3 ^2 is equal to: 2026The sum 1 + 1 2 (1^2 + 2^2) + 1 3 (1^2 + 2^2 + 3^2) + upto 10 terms is equal to : 2026The value of 1^3 - 2^3 + 3^3 - + 15^3 is: 2026The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8 . If the first term of the A.P. is equal to the common ratio of the G.P. and the 2026For the functions f( ) = ^2 + ^2 , and g( ) = ^2 + ^2 , > > 0 , let _ 0 < < /2 f( ) = _ 0 < < g( ) . If the first term of a G.P. is ( 2 ) , its common ratio is ( 2 ) and the sum of 2026If the sum of the first 10 terms of the series 1 1 + 1^4 4 + 2 1 + 2^4 4 + 3 1 + 3^4 4 + 4 1 + 4^4 4 + is m n , (m, n) = 1 , then m + n is equal to : 2026Let A₁, A₂, A₃, , A₃₉ be 39 arithmetic means between the numbers 59 and 159 . Then the mean of A₂₅, A₂₈, A₃₁ and A₃₆ is equal to : 2026Let the sum of the first n terms of an A.P. be 3n^2 + 5n . Then the sum of squares of the first 10 terms of the A.P. is: 2026 Full Sequences and Series list All JEE Main PYQs